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C <br />Table 3.5-6 - (continued) <br />Results of Trial and Error Solution: <br />d 0.996' <br />Q = 11.60 cfs O.K. <br />So, <br />Q = `JA <br />V = 11.60 cfs <br />2I0.99b)2 ft2 <br />V = 5.85 fps <br />A freeboard of 0.5 ft. is added for safety to d (Depth of Flov) for the <br />channel design. <br />D (d + 0.5) 0.996 + 0.5 - 1.496 ft. Depth of Channel <br />• T = 2(D)z = 2(1.496 ft)(2) - 6.0 ft. Top Width <br />• <br />3.5-Sj May 14,1993 <br />