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the cover data using the student's t-test found that the cover data was greater than 90% of the <br />standard with 90% statistical confidence; therefore, the revegetation on the reclaimed area <br />achieved the vegetation cover success standard for 2004. The minimum number of cover <br />transects required to achieve sample adequacy was 9 transects. Fifteen transects were <br />collected. Vegetative cover data achieved sample adequacy. <br />Production <br />Live herbaceous biomass measured 25.81g/1/4 m2 (air-dry weight). This value equals 103 <br />g/mZ or 921 Ibs/acre. The herbaceous production for 2004 measured from the reclaimed area <br />is nearly double the reclamation standard of 514 Ibs/acre (air-dry weight). Vegetative <br />production data did not achieved sample adequacy. The reverse null hypothesis is an <br />acceptable tool for evaluating data that does not achieve statistical sample adequacy and <br />contains a minimum sample size of thirty samples. Thirty production samples were collected. <br />The reverse null t-test is a statistically valid method for demonstration of success, when a <br />minimum of 30 sample observations have been collected, as was the case with this data set. <br />The null hypothesis being tested is that the bond release block mean for production (u) is less <br />than or equal to 90% of the production standard (Q) and can be stated as: H°: u< Q <br />If the hypothesis is rejected then the reclamation is considered successful for production given <br />the number of samples collected. Using the one-sample t-test, if the calculated value (t°) is <br />greater than the table (tt) value, then H° is rejected and the reclamation would still be <br />considered successful. <br />Reverse Null Formula <br />X-Q <br />/~, _ <br />.S- <br />s <br />x = 100.32 g/m2 = 895 Ibs/acre where x is the sample mean (in pounds/acre) <br />Q = 514 Ibs/acre x 90 % = 462.6 Ibs/acre where Q is 90% of the production standard (in pounds/acre) <br />Sx ~ 530 - 99.6 <br />s = 546 where s is the standard deviation (in pounds/acre) <br />n = 30 where n is the number of samples (30 production sample plots) <br />t~ = 895 Ibs/acre - 462.6 Ibs/acre = 4.34 <br />99.6 <br />t,°eie = Student's t values Principles and Procedures of Statistics Steele and Torrie (1980) <br />1 -tailed,0.1 a, n-I <br />= 1.310 <br />t~ > t1ea~~ 4.34 > 1.310 <br />