My WebLink
|
Help
|
About
|
Sign Out
Home
Browse
Search
WSP03104
CWCB
>
Water Supply Protection
>
Backfile
>
3001-4000
>
WSP03104
Metadata
Thumbnails
Annotations
Entry Properties
Last modified
1/26/2010 12:48:40 PM
Creation date
10/11/2006 11:32:19 PM
Metadata
Fields
Template:
Water Supply Protection
File Number
8143.600
Description
John Martin Reservoir
State
CO
Basin
Arkansas
Water Division
2
Date
7/31/1981
Title
RESSYM - A John Martin Reservoir System Simulation - written in CDC Fortran Extended Vers. 4
Water Supply Pro - Doc Type
Report/Study
There are no annotations on this page.
Document management portal powered by Laserfiche WebLink 9 © 1998-2015
Laserfiche.
All rights reserved.
/
9
PDF
Print
Pages to print
Enter page numbers and/or page ranges separated by commas. For example, 1,3,5-12.
After downloading, print the document using a PDF reader (e.g. Adobe Reader).
Show annotations
View images
View plain text
<br />2-3 <br />The simuldtion, then, implements the operdting principles dnu <br />o. computes, fro," ti,e given Ilydrololjlc do,ld, tile end or tile day stordlje <br />-0---- con L-e n-L-s-o n -d- U (_d.- L-y- -h.d.s-i .s_._ _^ 5_C.d 1I_1Je_ _.:.i.c_t: II_Lr U.ln_ LJI.e _,-aJ).0. v <; , _l!~w eve r ,__._ <br />("'~, there dre certain special condit ions under which water is to be <br />C1t stored in or reledsed from the conservdtion pool. The simple <br />C..l algorithms for edch condition dre stated in the following: <br />~ <br /> <br />1. For the period Nov. 1 to t1dr. 31 <br /> <br />5i= 5i-1+ Ii <br /> <br />(4) . <br /> <br />2. For the per iod Apc. 1 to Oct. 31, releases will cause <br />penetration of a criterial content level where the <br />contents IndIcate a change in release rate will occur, <br /> <br />a) \Vhen <br /> <br />20000 af < 5i_l+Ii< 22500 af <br /> <br />then <br /> <br />~ <br /> <br />5i=5i_1+1i-(5i_1+ li-20000)- <br /> <br />-[(1-(5i_l+1i-20000)/2500)](2000) <br /> <br />which simplifies to <br /> <br />5i= 20000-[(1-(5i_l. Ii-20000)/2500)](2000) (5); <br />b) \Vhen <br /> <br />5i+ Ii <= 2000 df <br /> <br />then <br /> <br />51 = 0 <br /> <br />(5-1) . <br /> <br />3. When <br /> <br />51_1=0 and Il>=IRQ . 1000 <br /> <br />where <br /> <br />IRQ = Irrigation requirement <br /> <br />then <br /> <br />5i = Ii <br /> <br />(6) . <br /> <br />4. When <br /> <br />5i_l = 0 and <br /> <br />Ii < IRQ + 1000 <br /> <br />then <br /> <br />----- -- -5r--=--O- <br />
The URL can be used to link to this page
Your browser does not support the video tag.