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<br />'.i <br /> <br />.' <br /> <br />. <br /> <br />O ."\ ."\ "j ~( '1 <br />~) u" ':'J <br /> <br />max salt =river x(},ver + volumeJ _ minconc x(},ver + actual x% return) <br />amount cone flow divertecf allowed flow return flow flow <br /> <br />(12) <br /> <br />where % return flow is the percent of the return flow that actually returns. <br /> <br />If the maximum amount of salt that can be removed is greater than the maximum <br />required to be removed, then <br /> <br />amount to be removed = maximum that can be removed <br />new sumsalt array = current sumsalt array - maximum salt that can be <br />removed <br /> <br />If the maximum amount of salt that can be removed is less than or equal than the <br />maximum required to be removed, then <br /> <br />amount to be removed = maximum amount that can be removed <br />new sumsalt array = current sumsalt array - amount to be removed <br /> <br />The amount removed expressed as mg/L is determined as: <br /> <br />amount removed <br /> <br />salt removed <br />shorted return flow x percentage return flow returned <br /> <br />(13) <br /> <br />This value is used as the salt pickup in the respective return flow. Since it is a <br />WQIP, it will be a negative number. <br />