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<br />4 <br /> <br />TECHNIQUES OF WATER-RESOURCES INVESTIGATIONS <br /> <br />of flow at the barrel entrance. <br /> <br />for the highest tailwater elevation selected <br />to submerge both the inlet and outlet. <br /> <br />If no results -are obtained in step I, the <br />sequence is: <br /> <br />2. Solve for hI by both the type 5 and <br /> <br />type 6 flow equations if the piezometric head <br />at section 1 is greater than 1. 5 D + z, or <br />solve for hl by the tyPe 3 flow: equation as <br /> <br />indicated, if supercl'itical flow occurred in <br />the section. <br /> <br />3. Solve for hI by the type 4 now equation <br /> <br />for the highest tailwater elevation, a-elected <br />to submerge both the inlet and outlet. <br /> <br />An outline of the computer program steps <br />for each type of flow is given below. For <br />now types 1-5, the sum of the potential and <br />kinetic heads at the upstreaIIl section are <br />equated to the Bum Qf the potential and kinetic <br />heads at the control section downstream plus <br />the friction and entrance losses between the <br />two sections. <br /> <br />Type 1 Flow <br /> <br />Critical depth OCcurs at the barrel en- <br /> <br />trance; therefore, the type 1 flow equation is: <br /> <br />2 <br />"'IQ <br /> <br />hi + ----:i = d2 + z + <br /> <br />2gA1 <br /> <br />Q2 <br />2 <br />2gA2 <br /> <br />+L L+(...!...-l\ <br />w Kl K2 C2 ) <br /> <br />Q2 <br />2 . <br />2gA2 <br /> <br />in which h is the piezometric head at the <br />1 <br />appro&.ch section. section 1, referred to the <br />elevation of the invert at the culvert outlet; <br />O'l (alpha) is the velocity-head coefficient at <br /> <br />the approach section; At is area of flow at <br /> <br />the approach section; d2 is .the depth of flow <br /> <br />at the barrel entrance, section 2; z is the <br />difference in elevation between the entrance <br />invert and the base (outlet invert) elevation; <br />L is the length of the reach between the <br />w <br />approach section and the barrel entrance; <br />Kl and K2 are the conveyances at approach <br /> <br />and entrance sections, respectively; C is the <br />~et discharge coefficient; and A2 is the area <br /> <br />The root of the equation is found by an <br />iterative process between two extremes, <br />The lower is the critical depth at the ap- <br />proach section for the selected discharge. <br />The elevation is obtained by interpolation be- <br />tween critical discharges computed in Part 1 <br />for the selected water- sur-face elevations at <br />the approach section. The upper extreme is <br />1.5 D + z. If no solution ..esults because the <br />piezometric head at section 1 is greater than <br />1. 5 D + z, solutions to flow equations for <br />types 5, 6, and 4 are attempted. <br /> <br />If no solution results because of super- <br />critical flow in the approach section. a mes- <br />sage. "NO SOLUTION TYPE ONE FLOW-- <br />SUPERCRITICAL FLOW AT APPROACH <br />SECTION,ll is printed. Then solutions for <br />successive type 3 conditions are tried and an <br />attempt is made to solve the type 4 flow <br />equation. <br /> <br />After a successful typ~ 1 solution, flow <br />equations for types 3 and 4 are solved if that <br />option is chosen. <br /> <br />Type 2 Flow <br /> <br />Type 2 flow requires two equations for <br />solution. Critical flow occurs at the barrel <br />outlet, section 3; therefol:'e, an equation for <br />flow within the culvert is first solved for <br />depth at the entrance, d2, This depth is then <br /> <br />used in another equation to solve for the head- <br />water elevation. <br /> <br />The first type 2 flow equation is <br /> <br />2 <br />d2 + Z + ~ <br />2gA2 <br /> <br />2 <br />= d + Q <br />3 2 A 2 <br />g 3 <br /> <br />Q2 <br />+LKK, <br />2 3 <br /> <br />in which d3 is depth of flow at the outlet cor- <br /> <br />responding to the critical discharge, L is the <br />barref length, and KS is the conveyance at the <br /> <br />outlet section. The root of the equation is <br />found by iteration between the two extremes,. <br />d2 = dc and d2 = D. <br /> <br />The second type 2 flow equation is <br />