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Last modified
7/29/2009 8:52:11 PM
Creation date
10/12/2006 3:28:31 AM
Metadata
Fields
Template:
Water Supply Protection
File Number
8040.100
Description
Section D General Studies-Power
Date
1/1/1981
Author
DOI
Title
Dunham Point-Peaking Power Unit-Plan of Study-Colorado River Storage Project Power Peaking Capacity
Water Supply Pro - Doc Type
Report/Study
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<br />. <br /> <br />ATTACHMENT A <br />POWER <br /> <br />Introduction to Peaking Power Concepts <br /> <br />Pea1(ing power is used to meet ''hi~'!1. level or short duration loads as <br /> <br />compared to sustained power that i.s used to meet avelag~ "'asp. l.oans. But. <br /> <br />unlike most of tl,e products we buy, power must he ~enerated at the same <br /> <br />moment as we buy i.t: it cannot be storen conveniently. <br /> <br />At any ~ !.ven <br /> <br />Moment. tl,e PToouction of power must 'be at least equa'l to tl-te demand from <br /> <br />lip-;l-tts. TV sets, air conditloners. refri~erato""s, fac:torv machinery, <br /> <br />etc. 'But demand vari.es from hour to hour, from day to day and season to <br /> <br />season. <br /> <br />For purposes of t~is discussi.on, tl-te. terms "capaci.ty" ari(l "energy" <br /> <br />are -identi.fied. <br /> <br />"capaci.ty" is consi.der.ed to be power and is measured in <br /> <br />. <br /> <br />"watts" or some mu'tiple sue" as ."ki lowatts" (~W). "Energv" .can be <br /> <br />t"ougl"t of as wor1<, .and i.s usually measuted in lI1<i1owatt-l-tout"s" ('kWl' ~ <br /> <br />Althou~h a generator may be able to produc~ enough en~rgv to supply a <br /> <br />citv. it may not have tl-te capacity to deliver tl,e energy in tl,e time <br /> <br />span it is needen. For example. a city may require a total of 2,400.000 <br /> <br />kl<1'1 of e1.ectri.city (energy) per day. A 100.000 kW plant operating for 24 <br /> <br />'lOurs (100,000 kW x 24 or. = 2.400,000 kWh) COil 1 " satisfy this demand. <br /> <br />HOlo7ever, the demand for electri.city during nav1-ight l-tOUTS l.S usually <br /> <br />~reater ttian at ni~ht and, as a resu1 t, 2,000;006 kHh of ener~v mi~ht be <br /> <br />required hetween the hours of 7:00 a.m. to 5:00 p.m. <br /> <br />So. at .least a <br /> <br />. <br /> <br />200,000 1<\~ (200,000 1<W x 10 hr. = 2.000,000 kWh) plant would be required <br />to meet this demand. The 400,000 kWh requiren between the hours of 1:00 <br /> <br />p.m. and 7:00 a.m. would theoretically he supplien at a rate of 28.571.4' <br /> <br />kW for. l4 l-tours. Thi.s example nemonstrates the concept of pea~<i.ng power <br /> <br />and why -it is important in an electri.cal power system. <br /> <br />1 <br /> <br />o '1 '?"; <br />
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