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2013-08-08_HYDROLOGY - M1977306
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2013-08-08_HYDROLOGY - M1977306
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Last modified
8/24/2016 5:23:35 PM
Creation date
8/12/2013 3:47:20 PM
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Template:
DRMS Permit Index
Permit No
M1977306
IBM Index Class Name
HYDROLOGY
Doc Date
8/8/2013
Doc Name
RESPONSE TO GENERAL STORMWATER COMMENTS
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OPERATOR
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DRMS
Email Name
DMC
TC1
Media Type
D
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No
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Proposed Sect. 30 -1 A, Runoff Collection Ditch, West of road, 3:1 side slopes <br />Note: This section analyzed at steepest slope (50 %) and lowest n (0.035) to give highest velocity <br />V = 8.34 fps = 2.542 mps (meters per sec) (from worksheets in attachment #3) <br />d = 0.31 ft = 0.0945 m (meter) <br />D5o = 0.00594 (V)3 / d0.5 K1.5 <br />D50 = 0.00594 (2.542)3 / (0.0945)0.5 (0.8944)'5 = 0.3753 meter = 14.8 inches <br />Therefore: 15" D5o specified is adequate <br />Proposed Sect. 30 -2A, Runoff Collection Ditch, West of road, 3:1 side slopes <br />Note: This section analyzed at steepest slope (17.5°x6) and lowest n (0.035) to give highest velocity <br />V = 5.62 fps = 1.713 mps (meters per sec) (from worksheets in attachment #3) <br />d = 0.38 ft = 0. 1158 m (meter) <br />D5o = 0.00594 (V) 3 / do-5 K' 5 <br />015o = 0.00594 (1.713)3 / (0.1158)0.5 (0.8944)' 5 = 0.103 meter = 4.0 inches <br />Therefore: 4" D50 specified is adequate <br />Proposed Sect. 30 -2C, Runoff Collection Ditch, Above pond, 3:1 side slopes <br />Note: This section analyzed at steepest slope (42.2 11x6) and lowest n (0.035) to give highest velocity <br />V = 8.38 fps = 2.5542 mps (meters per sec) (from worksheets in attachment #3) <br />d = 0.35 ft = 0.1067 m (meter) <br />D50 = 0.00594 (V) 3 / do-5 K'.5 <br />D50 = 0.00594 (2.5542)'/ (0.1067)0'5(0.8944)1 -5 = 0.3583 meter = 14.0 inches <br />Therefore: 14" Dso specified is adequate <br />Proposed Sect. 30 -2D, Runoff Collection Ditch, Above pond, 3:1 side slopes <br />Note: This section analyzed at steepest slope (33 %) and lowest n (0.035) to give highest velocity <br />V = 7.64 fps = 2.3287 mps (meters per sec) (from worksheets in attachment #3) <br />d = 0.37 ft = 0.1128 m (meter) <br />D. = 0.00594 (V)3 / d0 5 K'.5 <br />D50 = 0.00594 (2.3287)3 / (0.1128)05(0 8944)1.5 = 0.2641 meter = 10.2 inches <br />Therefore: 14° D50 specified is adequate <br />
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