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RULE 2 PERMITS <br />approximately 0.002 ft/day (H sandstone) to 0.008 ft /day (F sandstone), with a geometric mean of 0.006 <br />ft/day. Thus, calculating a single hydraulic conductivity (K) for pit wall seepage is difficult. For further <br />discussion, a K of 0.01 (1.0x10 -2) ft per day will be used. <br />The length of the northern pitwall is approximately 5000 ft. The thickness of the sandstones and coals <br />along this highwall (using actual core measurements and geophysical logs from three drill holes near the <br />proposed highwall) varies from a high of 84 feet thick to a low of 31 feet thick. The geometric average is <br />50.3 feet. Thus, the cross - sectional area (A) for the northern pitwall sandstones and coals is 2.52x105 <br />square feet. <br />With Q= KA(h/1), <br />K = 1.0x10.2 ft /day <br />A = 2.52x105 ftZ <br />h /1= 0.1 <br />This equals a minimum pit seepage volume of 252 cfd (0.005 acre -ft /day) over a height of 125 feet. <br />However, this pitwall seepage will only occur if a spoil aquifer is developed. <br />Based on the above, a spoil spring flow of up to 0.45 cfs from the Collom Lite Pit into the Little Collom <br />Gulch valley fill is possible. This is calculated as follows: the total surface infiltration into spoil is <br />calculated at 39,137 cfd. This number minus the calculated pitwall seepage of 252 cfd then equals a <br />possible spoil spring discharge of 38,885 cfd, which equals 0.45 cfs. This water would then flow down <br />Little Collom Gulch to Collom Gulch in Section 13, T. 4 N., R. 94W., if the spoil aquifer develops. <br />To determine possible impacts of this spoil water on Collom Gulch, data from valley fill testing needs to <br />be examined. Well testing of the monitoring wells in Collom and Little Collom Gulches showed a highly <br />permeable material. No hydraulic conductivity was calculated due to insufficient data (WMC, 2005). <br />Therefore, in determining probable ground water velocity for this spoil spring water, an average hydraulic <br />conductivity from the WMC report (2005) for valley fill material of 3.3 ft/day is used, an effective <br />porosity of 20% and a hydraulic gradient of 0.03 ft/ft (actual gradient in Collom Gulch and Little Collom <br />Gulch). This calculates a ground water velocity of approximately 0.5 feet /day. At this rate of travel, the <br />front edge of any spoil spring flow water transiting the Little Collom Gulch after exiting the Collom Lite <br />reclaimed pit would take approximately 95 years to reach Collom Gulch in Section 13, T. 4 N., R. 94W. <br />During this flow time, dilution of the water will occur due to infiltration through the valley fill materials <br />from precipitation, runoff and inflow from the bedrock units. <br />Prior to reaching Collom Gulch, the spoil spring flow water will encounter shallow ground water in the <br />valley fill in Little Collom Gulch. The amount of valley fill ground water currently transiting Little <br />Collom Gulch can be calculated using data from the WMC report. Using the data from MLC- 04 -01, the <br />average water level is 46.9 ft. below ground surface, a depth to bedrock of 66 ft., a valley width of 225 ft., <br />and a 20% effective porosity, calculates to a saturated area of approximately 430 square feet. Using <br />Q= KA(h /1), the minimum volume of water transiting Little Collom Gulch in section 13 is approximately <br />43 cfd, which equals 5x10 -4 cfs. <br />To determine the amount of valley fill water in Collom Gulch in Section 13, the probable valley fill water <br />amount at MC -04 -02 needs to be calculated. This Collom Gulch valley fill well is the closest to Section <br />13. Using an average water level of 11.25 feet below ground surface (from WMC data), a depth to <br />bedrock of approximately 85 feet, and a valley width of 325 feet, equals a cross sectional area of 11985 <br />square feet. Using a 20% effective porosity, the saturated area would equal 2396 square feet. Using <br />Q= KA(h/1), the minimum volume of water transiting Collom Gulch in section 13 is 237 cfd or 0.003 cfs. <br />Collom — Rule 2, Page 139 Revision Date: 9/28/11 <br />Revision No.: PR -03 <br />