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L. Perino Page 2 August 19, 1994 <br /> concrete under the entire downstream face of the waterstop. The <br /> line loads are assumed to be applied to the 4 inches of plate <br /> outside the 6. 625-inch diameter bypass pipe. The result of <br /> applying the maximum 8, 090 lbs to the bypass pipe is elastic <br /> elongation of the pipe between the thrust collar and the waterstop. <br /> The elastic modulus of the Schedule 80 (Extra Strong) 316L <br /> Stainless Steel is assumed to by 30, 000, 000 in/in This assumption <br /> is realistic for stainless steel in general. <br /> The calculation of the force ( P ) exerted by the waterstop <br /> against the concrete follows: I - moment of inertia of the assumed <br /> square, one-way supported beam. <br /> I = b a3 ; b = 4 in ; h = 0. 035 in I = 4(0 i�353) = 0.0000143 in <br /> 4 <br /> Extension of bypass pipe between thrust collar and waterstop: <br /> Stress on bypass pipe ( a ) : a= thrust _ 8090 = psi <br /> si <br /> area 8.40 <br /> Elastic modulus = E = stress = a E_ a __ 963 _ in <br /> strain ' E 30000000 — 0.0000321 in <br /> Bypass pipe extension ( 01 ) between the thrust collar at 5. 5 <br /> feet (66 inches) from the airside face of the bulkhead and <br /> waterstop 2 .75 feet (33 inches) from the airside face of the <br /> bulkhead: <br /> 1 = 0.0000321[(5. 5-2.75)12] = 0.00106 in <br /> Bypass pipe extension ( 01 ) equals the waterstop deflection at <br /> the welded attachment points of the waterstop to the pipe, two <br /> points, each 2 inches from both the assumed simple supports. <br /> Therefore, the equivalent force required to deflect the waterstop <br /> an equivalent distance ( Al ) at loading points "a" must be <br /> supported by the rebar tensile reinforcement. <br /> 01 _ Pa2[6Eli-4a] ; P— a[3(1)4a] <br /> _ [6(30000000)0.000014310.00106 2.73 _ <br /> P 22[3(10.625)-4(2)] 95.5 — 0. 0286 lb times two loading <br /> points equals 0. 0572 lbs of total waterstop load. <br /> If it is assumed that the waterstop is loaded in the center <br /> (simple beam, concentrated load at center) , the calculated force to <br /> produce 0. 00106 inches of deflection 2 inches from the simple edge <br /> supports is: <br /> 01 4' [3(12)-4x2] i P= (48EI)A1 <br /> x[3(12-4x2)] <br /> [48(30000000)0.0000143]0.00106 — 21.8 _ <br /> P_ 2[3(10.6252)-4(22)] 645 — 0. 0338 lb total waterstop load. <br />