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The time it takes for an object to drop 1.87 feet under the acceleration of gravity is calculated <br /> using the following equation: <br /> Distance = 1/2(acceleration) x (time)' <br /> or <br /> 1.87 feet = 1h(32.2 feet/second') x t' <br /> t = 0.341 seconds <br /> The exit velocity is calculated as follows: <br /> Velocity = [(20 feet) - (0.341 seconds)] _ cos 71/2 degrees <br /> = 59.2 feet/sec <br /> The cross-sectional area of the drill hole is calculated as: <br /> Area i= err' = it x(1/12)' = 0.0218 feet' <br /> The rate of flow is: <br /> Velocity x Area = 59.2 feet/sec x 0.0218 feet' = 1.29 feet'/second <br /> 1.29 feet'/sec x 60 sec/min x 7.48 gal/foot' = 579 gallons/minute <br /> This value is only accurate to one significant figure and is better expressed as: <br /> 6 x 10' gallons/minute <br /> sanjuan\sunny\11036 1\oct9 1.Rpt A - 3 <br /> a simon LUi �L, L-Fu <br /> � l J <br />