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2012-02-28_REVISION - M1980244 (72)
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2012-02-28_REVISION - M1980244 (72)
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Last modified
8/24/2016 4:49:12 PM
Creation date
3/15/2012 1:37:49 PM
Metadata
Fields
Template:
DRMS Permit Index
Permit No
M1980244
IBM Index Class Name
REVISION
Doc Date
2/28/2012
Doc Name
VOL 5, Appendix E: Sqaw Gulch VLF Slope Stability Results
From
CC&V
To
DRMS
Type & Sequence
AM10
Email Name
TC1
Media Type
D
Archive
No
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Infinite Slope Calculations <br />CLIENT <br />JOB NO. <br />TASK NO. <br />7 <br />PAGE 1 OF 2 <br />CC &V <br />1125G <br />A100 <br />PROJECT <br />CALCULATION No. <br />REV. No. <br />Squaw Gulch VLF <br />1 <br />1 <br />SUBJECT/ TITLE <br />REV. <br />PREPARER/ DATE <br />REVIEWER/ DATE <br />QA REVIEWER/ DATE <br />CONFIRMATION <br />NO. <br />REQUIRED Y/N <br />1 <br />Justin W. Hall 8106/10 <br />Derek T. Wittwer 8 /06 /10 <br />FS = b'tan(D <br />FS = b cP tan <br />l + bap <br />1.) For a FS= 1, (p =0.14 g, (D=40 degrees <br />b -0.14 <br />1 _ tan 40 <br />1 + b(0.14) <br />• 1[1 + (0.14b)] = (b — 0.14)tan 40 <br />1 +0.14b = 0.83b -0.117 <br />1.117 = 0.699b <br />• b =1.60 <br />Require 1.6:1 (horizontal to vertical) slopes for a FS of unity during a 0.14 g seismic event. <br />2.) For a FS =1, cp=0.08 g, 0=40 degrees <br />b-0.08 <br />• 1 = tan 40 <br />1 + b(0.08) <br />1[1 + b(0.08)] = (b — 0.08)tan 40 <br />• 1 + 0.08b = 0.83b — 0.067 <br />• 1.067 = 0.759b <br />• b =1.41 <br />Require 1.41:1 (horizontal to vertical) slopes for a FS of unity during a 0.08 g seismic event. <br />
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