2011-08-29_REVISION - M2005050 ‎(6)‎

• Permit No: M2005050
• IBM Index Class Name: REVISION
• Doc Date: 8/29/2011
• Doc Name: Submittal
• From: Rimrock Exploration and Development, Inc.
• To: DRMS
• Type & Sequence: TR2
• Email Name: GRM
• Media Type: D
• Archive: No

C - weir coefficient - 3.087 ft1/2 s -1
H - depth of flow
UPPER POND - with a flow of 3.7 cfs and a flow depth of 0.5 feet -
L = 3.7 / ( 3.087* 0.5 ^1.5) = 3.42 feet
SET WEIR LENGTH TO 4.0 FT
H = ( 3.7 / ( 3.087 *4.0 )) ^2/3 =
LOWER POND - with a flow of 13.3 cfs and a flow depth of 0.5 feet -
NOAA ATLAS 2
L= 13.3/(3.087 *0.5 "1.5) = 12.22 5.90 feet
SET WEIR LENGTH TO 16.0 FT
H = ( 13.3 / ( 3.087 *16.0 )y2 /3 = 0.42 feet or 5.0 inches
Y2 = 0.011 + 0.942 [(x1) (x1 /x2)]
where,
Y100 = 0.494 + 0.755 [(x3) (x3 /x4)]
where,
Y2 - 2 year, 1 hour estimated value (inch)
x1 - 2 year, 6 hour value (inch)
x2 - 2 year, 24 hour value (inch)
Y100 -100 year, 1 hour estimated value (inch)
x3 - 100 year, 6 hour value (inch)
x4 -100 year, 24 hour value (inch)
Y2(1 HR DEPTH) = 0.011 + 0.942 [(0.85) (0.85/1.15)]
Y100 (1 HR DEPTH): 0.494 + 0.755 [(1.9) (1.9/2.95)]
0.45 feet or 5.4 inches
0.603
1.418