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2010-04-05_REPORT - C1982057 (3)
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2010-04-05_REPORT - C1982057 (3)
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Last modified
8/24/2016 4:03:20 PM
Creation date
4/5/2010 2:04:36 PM
Metadata
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Template:
DRMS Permit Index
Permit No
C1982057
IBM Index Class Name
REPORT
Doc Date
4/5/2010
Doc Name
2009 Annual Revegetation Monitoring Report
From
Seneca Coal Company
To
DRMS
Permit Index Doc Type
Reveg Monitoring Report
Email Name
DTM
SB1
Media Type
D
Archive
No
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Were, after gathering 15 or more samples from the BRB, the mean allowable herbaceous cover <br />of the BRB to be greater than the reference area standard, then the hypothesis of reclamation <br />success would be tested using a parametric test of the "reverse null" hypothesis. This would be <br />conducted using the following expression (CDMG 2003 proposed rules revisions, 4.15.11 (2)(c)): <br />x-Q <br />tc _ <br />S- <br />r <br />Where: <br />X = Bond Release Block Sample Mean <br />Q = 90% of Standard <br />,S_ = Standard error of mean [ s / ,v n ] <br />X <br />S = Sample standard deviation <br />n = Sample size <br />t, = Calculated t value <br />tt = Table t value (alpha = 0.2) <br />The (reverse) null hypothesis being tested would be that the bond release block mean (u) was <br />• less than or equal to 90% of the standard, stated as Ho: u < Q. If t, was greater than the 1-tailed t <br />table value for alpha error probability of .20, with (n-1) degrees of freedom then Ho would be <br />rejected, and revegetation would be deemed successful. <br />Were the mean allowable herbaceous cover of an adequate sample from the 2009 Phase II BRB <br />was less than 90% of the cover standard (see above), then a one-sample t-test would be made in <br />the following form to test the hypothesis of reclamation success for cover (CDMG 2003 proposed <br />rules revisions, 4.15.11 (2)(b)): <br />t Q -x <br />S- <br />Where: <br />X = Bond Release Block Sample Mean <br />Q = 90% of Standard <br />SX = Standard error of mean I s / ?n ] <br />S = Sample standard deviation <br />• n = Sample size <br />t, = Calculated t value <br />t, = Table t value (alpha = 0.1) <br />6
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