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2010-03-10_PERMIT FILE - M2008012
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2010-03-10_PERMIT FILE - M2008012
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Last modified
8/24/2016 4:01:04 PM
Creation date
3/15/2010 10:16:33 AM
Metadata
Fields
Template:
DRMS Permit Index
Permit No
M2008012
IBM Index Class Name
PERMIT FILE
Doc Date
3/10/2010
Doc Name
Storm water management plan (part 1)
From
Nuvemco, LLC
To
DRMS
Email Name
GRM
ACS
DB2
Media Type
D
Archive
No
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NuvEMCO LAST CHANCE MINE <br />STORM WATER MANAGEMENT PLAN <br />W = minimum rock mass (size or weight) <br />V = velocity to which bank is exposed <br />SG = specific gravity of rock <br />r = 70 (for randomly place rubble, a constant) <br />a = outside slope face angle with horizontal, DEGREES <br />Assuming the stream section will be a constructed trapezoidal channel with 3H:1 V side <br />slopes, a = 18.43 °. <br />To compute the specific gravity of the riprap, the stone is assumed to be sandstone with a <br />weight of 145 pounds /cubic foot. Therefore: SG = 145/62.4 = 2.3 <br />Inputting the above into the equation: W = 0.2 pounds (See Appendix H) <br />Based on this, no riprap is required in the channel downstream of Sediment Pond #1. If <br />the channel shows signs of erosion, riprap will be installed. <br />Maximum Runoff Volume <br />The maximum runoff volume will be the 100 -year 24 -hour storm plus the 10 -year 24- <br />hour storm as outlined in the State of Colorado Division of Reclamation, Mining and <br />Safety's April 10, 2009 letter. From the NOAA Atlas 2, Volume the 10 -year 24 -hour <br />storm will generate 1.95 inches of precipitation. The 100 -year 24 -hour will generate 3.00 <br />inches. <br />It is assumed that none of the precipitation that falls on the area will infiltrate and all of <br />the precipitation will become runoff. This is a worse case. <br />100 -year 24 -hour precipitation event <br />3.00 inches = 0.25 feet <br />Net area = 46,996 sq ft <br />46,996 sq ft x 0.25 ft = 11,749 cu ft = 87,888 gallons <br />10 -year 24 -hour precipitation event <br />1.95 inches = 0.163 feet <br />46,996 sq ft x 0.163 ft = 7,660 cu ft = 57,301 gallons <br />The total volume from the two events equals 19,409 cu ft or 145,189 gallons. <br />By trial and error a pond, Sediment Pond #1, 54 ft wide by 54' long with 2:1 interior <br />slopes 5 feet deep will be required without any freeboard to contain the runoff from the <br />10 -yr 24 -hr storm with a 1 -foot deep spillway or outlet into the Swale that runs northeast. <br />Other shapes that fit the area may be constructed if they have an equivalent volume. <br />March 2010 <br />
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