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• Sediment Pond F <br /> RIPRAP SIZING - Spillway Channel Down Face of Embankment <br /> D50 = Size of Riprap <br /> D50 = ( (V X S^ . 17)/7 .58) ) ^2 <br /> D50 = Diameter in feet <br /> V = Velocity <br /> S = Slope <br /> D50 = 1.079 feet v' 12 .953 inches <br /> The spillway for sediment pond F will be a trapezoidal <br /> channel 10.0 feet wide and 1. 10 feet deep <br /> with a freeboard of 12" for a total depth of 2 . 100 <br /> feet. Riprap, 6" minus, will be placed in the spillway <br /> channel across the top of the embankment and riprap, <br /> 14 inch minus, will be placed in the spillway channel down <br /> the face of the embankment. <br /> SEDIMENT POND F - DEWATERING PIPE - 6" Diameter PIP <br /> DISCHARGE UNDER FALLING HEAD <br /> Assume of pond is constant with varying height. <br /> AREA OF POND = A 75200 SQUARE FEET <br /> DIAMETER OF PIPE 6.00 INCHES <br /> • AREA OF PIPE = a 0. 1963 SQUARE FEET <br /> C = LOSS COEFFICIENT 0. 650 <br /> H1 = BEGINNING HEAD 3 . 00 FEET <br /> H2 = ENDING HEAD 0. 00 <br /> t = time to lower the surface level of the pond (H1-H2) . <br /> t = 2A* (H1^ .5 - H2^ . 5)/C*a* (2G) ^ .5 <br /> t = 254473 SECONDS <br /> t = 2 .95 DAYS +S g5 GCS <br /> Average flow in pipe: 397 GPM <br /> Reference Civil Engineering Handbook, <br /> Urquhart, Fourth Edition, Page 4-34. <br /> CHECH FRICTION LOSS IN PIPE <br /> C = surface roughness constant 150. 000 <br /> q = flow in gpm 397. 000 <br /> d = inside diameter of pipe, inches 6. 000 <br /> f=0. 2083* ( (100/F6) ^1.85) * (F7^1.85)/ (F8^4 .8655 1. 034 /100 ft <br /> Slope Pipe 2 % to compensate for head loss. <br /> • <br /> 9-30 July 1992 <br />