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<br /> <br />Table 2.2-1. Reverse null T-Test on mean to demonstrate revegetation success for production and shrub density values. <br />Sample Parameters <br />Mean (Xbar) <br />Standard Deviation (S) <br />Standard Error (S),bar) <br />[S/(n)vz] <br />Sample Size (n) <br />Q = 90% of standard <br />Table T Value = Tt <br />(alpha = .20; df = 29 or 47) <br />Calculated T Value = Tc <br />T,=Xbar - Q <br />Sxbar <br /> A,D&H Pits RSA&B <br />Plant Production Shrub Density <br />(grams p er 1/4 m2) (shrubs p er 100 m2) <br />2007 2008 2007 2008 <br />38.9 61.8 19.1 15.5 <br />17.9 35.0 24.2 37.8 <br />3.27 6.39 4.42 5.46 <br />30 *' 30 *' 30 48 <br />14.04 *2 14.04 *2 8.89 *3 8.89 '3 <br />0.84 0.84 0.84 0.84 <br />7.61 7.47 2.31 1.21 <br />Note: If Tc > than Tt, then the null hypothesis (Ho) is rejected and revegetation is deemed successful. <br />Three clip plots per transect, thus 90 total samples collected. <br />*2 Actual standard = 62.39 grams per m2. (62.39 / 4 (sampled plots = grams per 1/4 m) * 0.9 (90% of standard) = 14.04.) <br />*3 Actual standard = 400 shrubs per acre. (4051.1 m2 in an acre = .0987 shrubs/m2 * 100 m2 transect = 9.87 * 0.9 (90% of standard) = 8.89.)