2008-01-28_PERMIT FILE - C1992080A

• Permit No: C1992080A
• IBM Index Class Name: Permit File
• Doc Date: 1/28/2008
• Section_Exhibit Name: APPENDIX 5-2 SEDIMENT POND CONTROL DESIGN
• Media Type: D
• Archive: Yes

Calculation Sheet 3 of 5
PCI Sedimenc Pond lil
As Built
From Equation (f)
Tmo = Td + Tmi = 24 h. + .522 hr.
= 24.522 hr.
•
From Equation (e)
Solve for Qpo coefficients
Tri = .637 hr. _ ,443 hr2/in2
(Qpi) (V) (1.617 in/hr) (.89 in)
3 Tmo - Tbi = (3) (24.522 hr) - (1.101 hr) = 81.421 hr/in
V .89 in.
Equations (e) becomes
.443 Qpo2 + 81.421 Qpo - 2 = 0
This is a quadratic equation solved by
Qpo = -81.421 + (81.421)2 - (4)(.443)(-2)
(2) (.443)
_ .025 in/hr.
From Equation (i)
S = storage volume = Tbi (Qpi Qpo)/2
= 1.101 hr. (1.617 in/hr - .025 in/hr)/2
_ .876 in.
81.421 + 81.443
.886