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~, -~ $~ <br />p~~EO ~2/~1~3 <br />WFC SUBMITTAL 4 <br />EFFECTS OF CAPILLARY RISE IN COAL PROCESSING WASTE DUMP <br />(CIRUELA CANYON) <br />The following computations are intended to examine the potential effect of <br />capillary rise of waters in the gravel materials into the overlying waste dump. The <br />approach was to estimate the height of capillary rise into the waste material, assuming <br />that the water table in the gravel is positioned at the interface between the gravel and <br />the waste material. By this means the volume of water potentially affected by contact <br />with the waste is estimated. It is further assumed that this volume is entirely drained <br />once the water table recedes, and that this cycle occurs once annually. It can be <br />demonstrated by experiment and by theoretical calculations that drainage of a fine <br />grained material overlying a coarse grained material is greatly impeded by this presence <br />of the coarse material. Therefore, the assumption that complete drainage occurs is highly <br />biased toward a worst case estimate. <br />No measurements of the height of the capillary fringe in the waste material are <br />available. Therefore, the height is estiamted from the equation ('McWhorter and Nelson, <br />1978)*; <br />hd = 9.66 (K/n)-0.401 <br />where: <br />hd =height of capillary fringe; cm <br />K =permeability, cm/s <br />n =porosity, dimensionsless fraction <br />A reasonable estimate for the permeability of the waste material (s 5x10-4 cm/s and <br />the porosity is expected to be near 0.4. These values yield <br />hd = 9.66 (5x10-4)-0.401 = 140 cm <br />= 4.6 ft <br />The area of contact between the waste material and the gravel is taken to be 10 <br />acres. Thus, the volume of capillary water contacting the water is <br />Volume=lOx4.6x0.4= 18.4 ac-ft <br />The next step was to calculate the change in water quality in the Purgatoire River <br />as a result of addition of 18.4 ac-ft of water with a degraded quality. This was <br />accomplished with means of the mass balance. <br />CaQ=QCb+QwCw <br />or <br />QC=Ca-Cb=CwQw/Q <br />