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• Sediment Pond F <br />RIPRAP SIZING - Spillway Channel Down Face of Embankment <br />D50 = Size of Riprap <br />D50 = ((V X S^.17)/7.58))^2 <br />D50 = Diameter in feet <br />V = Velocity <br />S = Slope <br />D50 = 1.079 feet 12.953 inches <br />The spillway for sediment pond F will be a trapezoidal <br />channel 10.0 feet wide and 1.10 feet deep <br />with a freeboard of 12" for a total depth of 2.100 <br />feet. Riprap, 6" minus, will be placed in the spillway <br />channel across the top of the embankment and riprap, <br />14 inch minus, will be placed in the spillway channel down <br />the face of the embankment. <br />SEDIMENT POND F - DEWATERING PIPE - 6" Diameter PIP <br />DISCHARGE UNDER FALLING HEAD <br />Assume of pond is constant with varying height. <br />AREA OF POND = A 75200 SQUARE FEET <br />DIAMETER OF PIPE 6.00 INCHES <br />• <br />AREA OF PIPE = a 0.1963 SQUARE FEET <br />C = LOSS COEFFICIENT 0.650 <br />H1 = BEGINNING HEAD 3.00 FEET <br />H2 = ENDING HEAD 0.00 <br />t = time to lower the surface level of the pond (H1-H2). <br />t = 2A*(H1^.5 - H2^.5)/C*a*(2G)^.5 <br />t = 254473 SECONDS <br />t = 2.95 DAYS <br />Average flow in pipe: 397 GPM <br />Reference Civil Engineering Handbook, <br />Urquhart, Fourth Edition, Page 4-34. <br />CHECH FRICTION LOSS IN PIPE <br />C = surface roughness constant <br />q = flow in gpm <br />d = inside diameter of pipe, inches <br />f=0.2083*((100/F6)^1.85)*(F7^1.85)/(F8^4.8655 <br />Slope Pipe 2 % to compensate for head loss. <br />• <br />150.000 <br />397.000 <br />6.000 <br />1.034 /100 ft <br />9-30 July 1992 <br />