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' D50(Straight) = 1.48 FT ~'+`'F <br />to on curves <br />~b = 2.65 M(r/w) - 0.5 <br />`rb =(2.65)(6.09)(200/72.14)-0.5 = 9.96 PSF <br />Dgp (200' RAD.) = Tb/0.04 (XS -X ) <br />D50 (200' RAD.) = 9.69/(0.04)(165 - 62.4) = 2.4 F7 <br />For D50 = 2.4': <br />% smaller intermediate rock dimension (incfies) <br />Z 0-100 48 <br />SO-70 36 <br />35-50 30 <br />2-l0 12 <br /> <br /> <br /> <br /> <br /> <br />M_ <br />