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APPENDIX 2.05.3-5C (Continued) <br />Riprap - Culvert No. 10 <br />Determine riprap size <br />Da = 1.5 Q = 1.13 Yt = .29 <br />Yt = 29 ;19 <br />0 1? <br />Q = 1.3 = 1.3 .71 <br />Dim l 1~3 i~4 <br />Type L = D50 = 9,~ <br />Expansion Factor 1/(2 tan 8) <br />Q = 1.3 = 1.3 = .47 <br />p~ :: 5 1, 52-5 ~.T6 <br />1/(2 tan B) = 5.5 <br />Determine length of riprap protection <br />L = (2 tan A)(At/Yt -W) <br />• <br />L = length in protection <br />At = Q = 1.13 = ,57 <br />V ~. ~ <br /> <br />L = 5.31 feet <br />D =pipe diameter in feet <br />Yt = tailwater depth in feet <br />Q =discharge in cubic feet per second <br />L =length of riprap <br />At = cross-section area at flow depth <br />V =velocity feet per second (fps) <br /> <br />- 245 - (Rev. 5/86) <br />