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0 <br />0 <br />0 <br />o ° T = 2640 (Q) = 264 i24gpm) = 377.14 gpd/ft. = 4.68 mz/day <br />° S = 0~ to _ 0.3 377.14 gpd/ft .028 days = p.8 x 10 ' <br />r (10.5)z <br />1 <br />y <br />v <br />v <br />in .•- <br />3 3 <br />~ o <br />3 <br />~o <br />L <br />G <br />2 <br />to = 40 min. ~Q <br />r = 10.5 \ <br />Q=2 gpm o~ <br />T = 377.14 gpd/ft. = 4.68 m2/day <br />S = 2.8 x 10'Z o <br />O \ <br />O \\O p <br />° <br />° <br />O ° <br />Time (t) From Start of Pump in i4inutes <br />• <br /> <br />M <br />a~ <br />