Laserfiche WebLink
Bulkhead Design <br />Page 3 <br />Design for Shear <br />Cf, = 1.7 Yc = 1.7 x 62,064 lbs. = 105,509 lbs <br />= 105.5 Kips <br />~'/ = 1.7 ~ = 1.7 x 93,096 lbs. = 158,263 lbs. <br />= 158.3 Kips <br />= 15.8 Kips per ft. <br />~'W = Vw = 105,509 lbs = 287 psi <br />0bd 0.85 x 24 x i8 <br />287 psi ~ 110 psi = Vc = 2 f'c = 2 3,000 <br />. nominal shear carried by concrete, <br />web reinforcement is required. <br />Y~ _ ( YM - V.) = 287 psi - 110 psi = 177 psi <br />177 psi ~ f'c = 3000 = 438 psi <br />Cross section need not be increased <br />a = (L-d) (~(~) _ (60 in - 18 in) x 177 psi <br />2 Yu 287 psi <br />= 42.0 x .619 = 25.9" <br />d + a = 18" + 25.9" = 43.9" <br />2 - Y~ - <br />_ (60 in - 18 in) 177 + 110/2 <br />287 <br />= 42 in x .81 - 34 in. <br />287 ~ 4 f'c = 219 ~ distance from supports to which <br />stirrups need to be placed = <br />a'd = 18" + 34" = 52" <br />.'. two stirrups must intercept a potential diagonal crack <br />S = Avfy = 0.62) 60,000 = 8.757" _~ 8 3/4 in2 <br />Y'b 177 24 <br />Av = 50 (24) 8.76 = 0.18 in2 <br />60,000 <br />0.18 in2 0.40 in2 '• OK <br />