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Meadow Land Diversity <br />Affected Area <br />n1= 10 <br />= 18.4 <br />xl <br />s1= 409.66 <br />Reference <br />n2= 11 <br />x = 170 <br />2 <br />sx= 388.65 <br />H u = uz and there is essentially no difference between <br />tie group <br />t = vl - xz <br />1/N1 x 1/NZ <br />t = 10 - 11 <br />419.25 1/10 + 1/11 <br />t = .006 with 19 d.f. <br />= N1 SZ + NZ SZ <br />N1 +NZ - 2 <br />= 419.25 <br />On basis of 2 tailed test at 95% confidence level we can <br />and Q.. <br />accept Ho since the t value of .006 for 19 degrees of <br />freedom is between -2.093 to 2.093. <br />