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<br />t test for percent cover of meadow land <br />Affected Reference <br />xl = 7.55 <br />nl = 10 <br />sl = 16.72 <br />n2 = 11 <br />xZ = 6.57 <br />sZ = 14.96 <br />Ho ul = u2 and there is essentially no difference between <br />sample means <br />xl - Xz <br />2 2 <br />t ~ 1/N + 1/NZ where N1S1 + NZSZ <br />1 6 <br />Nl + NZ - 2 <br />x z <br />~, = 10(16.7) + 11 (14.9) <br />10+11 - 2 <br />~ = 21.80 <br />t = .1146 <br />Since our t value for 19 degrees of freedom falls within our <br />range of -2.093 to + 2.093 we can conclude from our hypothesis <br />Ho that there is eeeentially no difference between samples. <br />