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t test for meadow land productivity <br />Affected <br />x = 271.8 <br />1 <br />sl= 188.6 <br />n1= 20 <br />Ho ul = uz <br />Reference <br />x = 262.0 <br />2 <br />sz= 138.0 <br />nz= 20 <br />there is essentially no difference between <br />population groups <br />t = X1 - Xp <br />~ /N1 + 1/Nz <br />wher <br />2 2 <br />e N1S1 + NzSz <br />~' P71 + Nz - 2 <br />20 (188.6)z + 20 (138)z <br />20+20- 2 <br />= 447.7 <br />t = 271.8 - 262.0 <br />447.7 1/20 + 1/20 <br />t = 0.21 <br />CFn basis of 2 tailed test at 0.5 level of significance we can <br />conclude that since our t value of 0.21 is between - 2.025 <br />and 2.025 for 38 degrees of freedon there is no significance <br />difference. <br />