Laserfiche WebLink
Mogul Mine bulkhead design Page 6 <br />Solution to Bernoulli equation <br />C P + 2gc +ZI)+hA = ( P + 2& +Z2) +hg+hf <br />62.4 0.425523 1/-0 0.425522 2.28(0.18107) 0.04(30)0.18107 <br />062.4 + 2(322)D~ +~ +~ - 162.4 + 2(32.2)D~ +~)+0+ 2(32.2)D4 + 2D1(32.2) <br />0.0064]29 0.0033752 <br />IA= p. + ps <br />0 = 1.OD5 - 0.0064129D - 0.0033752 <br />July 14, 2003 <br />D = 0.3351 ft (4.261 in} for welded and seamless steel pipe <br />A 4.5-in nominal diameter Schedule 40 standard weight steel pipe <br />((4.536-in (0.3780-ft) inside diameter] will meet the bypass flow <br />requirement. <br />Calculate "f" (Moody friction factor) based on associated Reynolds <br />number (NRe) <br />N~=~U Et = kinematic viscosity = 1.405 x 10'5 fl~ <br />__ Q Iso(o.oozz2s) __ o.a2ssz <br />p A = •0~ De <br />Ocu D<(0.42552) _ 0.42552 _ 0.42552 <br />NRE - N - D~ D~ (0.3780x1.405210_5) - 8.OI22 X I04 <br />E = 0.0002 <br />E °0'°-0°2 - 0.00052910 <br />D~ - 0.3780 - <br />f = 0.0210 <br />l`0'+2~ +L1~+liA=`o +2& J-X21+hg+hf <br />p 2-20, Table 3.8 <br />p 2-21, Figure 3.13 <br />62.4 0.425522 0 0.425522 228(0.78107) 0.0270(30x1.78107 <br />62.4 + 2(322)D~ +~ +~ - 062.4 + 2(322)D4 +0)+0+ 2(32.2)Dd + 2D5(32.2) <br />1.Oft = 0.0064104 0.0017713 <br />pa + ps <br />0 = 1.ODe5 - 0.0064104 De - 0.0017713 <br />D = 0.3295 ft (3.954 in) <br />A 4-in nominal diameter Schedule 40 standard weight stainless <br />steel pipe (4.026-in (0.3355-ft) inside diameter] will meet the <br />bypass flow requirement. <br />..... 4 ~ - <br />..- <br />a c' <br />...: ~ t -_::... sFaA ~) ~`?air t'i~ ^n ; :_. - <br />