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For our example the hypotheses are: <br />Ho~ Ii1=µ2=µ3=lx4=µ5 <br />Ha: the mean cover values are not equal <br />The summary of the calculations for the ANOV are presented in the following table. <br />Source of Variation Sum of wares of blreedom Mean ware <br />Total 1592.67 16 <br />Groups 538.34 3 179.45 <br />Error 1054.13 13 81.09 <br />The test for equality of means in ANOV is the variance ration test F: <br />F= group Mean Square/error Mean Square <br />F = 179.45181.09 = 2.21 <br />The critical values of the F statistic for 95% confidence is: <br />Fo.oSp>,3.ts= 3.41 <br />Therefore, do not reject Ho: µt=µ2=µ3=µa=µ5 <br />The sample means are equal, therefore they come from the same population, and the <br />population is homogenous. <br />COMPARISON OF HOMOGENEITY WITH NORTHERN # 1 EAST DATA <br />As mentioned earlier, the permittee elected to exclude the Northern # 1 East Side Area <br />from consideration for Phase II bond release based on the lower vegetation cover values <br />obtained during 1992 field sampling. As further analysis of the homogeneity of the <br />vegetation populations, separate analyses of homogeneity were performed which <br />included the Northern # 1 East Side Area vegetation cover data. The same tests <br />(Bartlett's Test for homogeneity of variances and Analysis of Variance) were <br />undertaken. Results ate provided below. <br />BARTLETT'S TEST (includioe NORTHERN # 1 EAST SIDE) <br />The sample data for this demonstration are the vegetation cover data from the Northern <br /># 1 Mine Area- West Side (N#1 West), Northern # 1 Mine- Topsoil Stockpile Area <br />(N#1 T/S), Refuse Area- Topsoil Stockpile Area (R.A. T/S), Refuse Area (R.A.), and <br />Rienau # 2 Mine Area (R#2), and Nordurn # 1 Mine Area- East Side (N#1 East) <br />These data are presented in full in the vegetation data section of this submittal. <br />