PERMFILE70089

• Permit No: C1981026
• IBM Index Class Name: Permit File
• Doc Date: 9/14/1981
• Doc Name: RESPONSES TO PHASE I APPARENT COMPLETENESS REVIEW AND COMMENTS FROM CMLR OF 09/2/81
• Section_Exhibit Name: ADDENDUM II
• Media Type: D
• Archive: No

158
H
H
F-
LL
2
d
0
In
CHAPTER
0
5
0
S- 2 ~t gt2 Ot
4
2
3 2
1-
tL
= S-2~t
2 a I
0
to
N $+~~}
4
I + 00 I 2 3 4
SI Z'o` ~ gz+ 221 Sf ~ ~t
~O 10 20 30 40 50 Fi("
$tZ~t
Pi_^_ure 3.1 I. Example of routing usm^_ PULS method. Thr chanc[tnstic turves arc
from Fsamplt Problem 4.3.
('_) Solcc for S•+ ~~ ~t by adding (11 +I~)~t/_'to Sl-~~ „t.
[3) En[rr Ihr stongt charactrristir to rvcs at the new' vahte o(S_. + ~= p t and
read oft H•.
(1) Drtcmunc the value of O, from tltc stage discharge vrvc corn•:ponding to
H,.
(5) Rrpca[ [hr procedure by setting [hc new 11, OI, SI and Hi equal m [hr
pm~ious I+. O+. S, and H. and using a new I+. Continut until tht rowing
~mPlttt. - -
:~-
..~.- .
HYDRAULICS OF STRUCTURES
Exantplr Problem 4.4
An innow hydrograph is shown in ttte first two columns of the followu~.
Route the hydrograph through the structure of Example Problem 4.3.
Solution:
Tht solution is shown in tabular form in tht following table along wet.
now hydrograph.
(1) ('-) (3) (4) (5) (6) (7)
Time 1 (11 +1.)Gt/? Hi St -OI 0t/3 S,+O+ pt/? H,
(min) c(s aoft ft ac-ft ac-ft ft
0 0
5 30 .14 0 0.50 0.64 0.09
10 IS? .77 0.09 0.63 1.39 0.4.
I S 379 1.95 0.4' I..0 3.15 1.08
'0 548 3.3? 1.08 ?.35 5.57 1.60
'S 64i 4.14 1.60 4.50 8.64 '_.I'_
30 677 4.59 '_.1'_ 7.?0 II.79 '_.55
35 651 4.61 ?.55 10.05 14.66 3.90
40 59'_ 4.3'_ '_'.90 13.'_0 17.5 3.17
46 510 3.83 3.17 IS.ti0 19.43 3.35
50 4"_ 3._4 3.35 17.60 '0.84 3.35
55 334 '`.66 3.45 18.50 =1.16 3.50
60 '_70 3.13 3.50 19.'0 '_1.33 3.50
6_07 1.66 3.50 19.50 ' 1.16 3.50
70 I50 1.34 3.50 19.'_0 '_0.40 3.4'_
75 I10 .90 3A7 18'0 19.10 331
SO b0 .66 3.31 1750 15.16 3.'_'
SS 50 .45 3... 16.00 Ifi.45 3.05
Thr ealndaitd ow Dow hydro graph is plotted along with the innow hydrogr;
F~gurc 3.1 =.
Charactrnsurs of Hyd rocs phs
The relationship of stone to iht relative m0ow and outflow hyd rocr_
shown m Fi^_urr 3.13. It can b r show n That tltc peak d ischarge of the outllow Ir.
graph corresponds [o [hc point of mta rscction of the nv o hydrographs. Thecontu
cy nation can hr wnttcn as
dS=I-O
(~
d[
For the time when outnow is niaxununt, tlrc storago wd also br maximum. We
rind the Point a which S is a maximum by setting T equal to zero. Therefore,
maximum storage and outllow rate will occur when inflow 1 tyuas ou[now O. Tlu_
course. cortrsponds to the points of in trrsection. The stonee volume required in
rrx rvoir is the arcs between the m0ow and outflow by hs prior to the pr
outllow and is also the area brhrern the nvo hyd rocrapl. e peak outno~~
.. ~ r ..