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beak <br /> <br />(A)2/3 = V n <br />P (1/5)(S') <br />A _ V n l3/2 <br />A 3/2 <br />V n <br />P = <br />(I.5)(S~) <br />• <br />3. Solve for P if V = 5.0 ft/S ~ A = Q/V = 3.2 ft2 <br />3.2 ft2 <br />P = (5.0 ft/s (0.05 3/2 = 8,363 ft <br />(1.5)(0.1) <br />x <br />4. Ditch Geometry. Y ~ // <br />z <br />A=1/2 Y.Y P=Z+Y <br />X = YA <br /> <br />Assume Y and solve by trial and error until P = 8.363 ft <br />If Y = 0.858' _> X = 7.459' _> P = 8.366' <br /> <br />• <br />