PERMFILE54026

• Permit No: C1985070
• IBM Index Class Name: Permit File
• Doc Date: 12/11/2001
• Section_Exhibit Name: EXHIBIT 7 DRAINAGE AND SEDIMENT CONTROL PLAN
• Media Type: D
• Archive: No

• Equivalent Area
where L = hydraulic length
Ae = 1.83
Equivalent Peak Discharge
EPD = 2.3cfs/inch of runoff(3)
10 year, 24 hour = 0.66cfs
25 year, 24 hour = 1.lOcfs
Actual Peak Discharge
APD = EPD x SAF x DA/Ae
10 year, 24 hour = 3.Ocfs
25 year, 24 hour = 4.9cfs
Runoff Volume
Vr = (DA x Q)12
• 10 year, 24 hour = 0.20ac-ft
25 year, 24 hour = 0.33ac-ft
Sediment Calculations
R = 351
K = .242
LS = .183
CP = 14
Sediment Yield
35(.24)(.18)(1) = 1.51 tons/ac
(1.51 tons/ac)(8.2 ac)3 year = 37.1 tons
(37.1 tons)(2000 lb/ton)(cu-ft/90 lb)
(ac-ft/43560 cu-ft) _ .02 ac-ft
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