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For the area upstream of the confluence with Santa Clara Creek: <br />• 010 = 0144 (2.57)0.528 (133.55)0.336 = 1228 cfs <br />025 = [891 (2.57)0.4827 (133:55)0.154 = 2984 cfs <br />0100 = 01770 (2.57)0.463 (133.55)0.086 = 4174 cfs <br />Method 3 Soil Conservation Service Method <br />1. Summarize data <br />Curve number (Tables 2.04.7(2)-1 and 2.04.7(2)-2) <br />CN 75 <br />Hydraulic length, L 16,000 ft. <br />Elev, difference between point of interest and watershed <br />divide, <br />H = 795 ft. <br />Drainage agea, A = 1.56 square miles = 998 ac <br />• 24-hour precipitation <br />10-year P24 = 3.0 inches <br />25-Year P24 = 3.8 inches <br />100-year P24 = 4.6 inches <br />2. Determine runoff, fl(inches) (Table 2.04.7(2)-3) <br />CN = 75 <br />10-year 0 0.96 <br />25-Year fl 1.53 <br />100-year 0 2.14 <br />3. Determine qp (cfs/inch) <br />Using 'L, find equivalent drainage area, De (Figure 2.04.7(2)-2) <br />De = 1400 ac <br />Equivalent peak flow, qe for De (Figure 2.04.7(2)-3) <br />CN = 75 9e = 550 <br />CN 75 qp = (998/1400) 550 = 392 <br />_ a "s' 1~tYC131 <br />JFSA- 38 <br />Z E $i4TO & ASSOCIATES,. INC. <br />