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PERMFILE42075
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PERMFILE42075
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Last modified
8/24/2016 10:44:36 PM
Creation date
11/20/2007 11:00:57 AM
Metadata
Fields
Template:
DRMS Permit Index
Permit No
C1981033A
IBM Index Class Name
Permit File
Doc Date
12/11/2001
Section_Exhibit Name
EXHIBIT 11 DRAINAGE AND SEDIMENT CONTROL PLAN
Media Type
D
Archive
Yes
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Sear No. 3 Mine <br />Sediment Pond Operations <br />• The sediment pond at the Bear No. 3 Mine ie shown on Map 11-3. The <br />pond is designed to contain the run-off Prom the l0 year 24 hour <br />event. Dewatering of the pond will be required at any time the water <br />level in the pond is above elevation 6003.5, in order to maintain <br />the required 0.75 AF storage volume. Devaterinq of the water from <br />a significant storm event will occur after the water has been <br />allowed to settle for 24 to 48 hours. <br />The outlet pipe for the ponfl consists oP a 12" CMP. The pipe vas <br />installed incorrectly with the outlet being higher than the inlet. <br />The invert of the inlet end of the pike is at elevation 6002.9. <br />The invert of the outlet end of the pipe is at elevation 6003.2. <br />For this reason the maximum sediment level in the pond is elevation <br />6002.9 and the minimum water level in the pond is elevation 6003.2. <br />Therefore there is dead water storage in the pond between elevations <br />6002.9 and 6003.2. This dead water storage causes the "gap" in the <br />stage filling diagram presented on drawing 11-3. <br />Pond Devatering <br />The pond will be dewatered by opening the normally closed slide gate <br />on the 12" CMP pipe. Use the following formula for discharge under <br />falling head to determine the time it texas to dewater the pond. <br />DISCHARGE UNDER FALLING HEAD <br />Assume area of pond must be constant with varinq <br />• height. Use average surface area of pond. <br />Surface Area of Pond. 13390 SQUARE FEET <br />Diameter of Pipe 12 INCHES <br />Area oP Pipe = a 0.7850 SQUARE FEET <br />C = Loss Coefficient 0.65 <br />H1 Beginning Head 2.7 FEET Elevation 6005.9 <br />H2 = Ending Head 1.0 Elevation 6004.2 <br />t = time to lower the surface level of the <br />pond (H1-H2) <br />t = 2A*(H1^.5 - H2^.5)/C*a*(2G) <br />t 4206 <br />t = 70.1 <br />t = 1.2 <br />t = 0.05 <br />gpm = 2429 <br />Cfs 5.4 <br />^.5 <br />Seconds <br />Minutes <br />Hours . <br />DAYS <br />Gallons per Minute <br />Cubic Feat par Second <br />Reference Civil Engineering Handbook, <br />Urquhart, Fourth Edition, Page 4-34. <br />11-12 Nev August 4, 1993 <br />• <br />
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