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APPCOR13152
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APPCOR13152
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Last modified
8/24/2016 6:33:26 PM
Creation date
11/19/2007 2:38:39 PM
Metadata
Fields
Template:
DRMS Permit Index
Permit No
C1981031
IBM Index Class Name
Application Correspondence
Doc Date
9/30/1983
Doc Name
STIPULATION NO. 3 RESPONSES
From
J F SATO & ASSOCIATES
To
MLRD
Media Type
D
Archive
No
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EXHIBIT B <br />Sediment Calculations <br />Reference: National Cooperative Highway Research Program <br />Report 221, Transportion Research Board, Apri1.1980. . <br />General equation: A R x K x LS x VM <br />R: From Figure 5.2, R is 70 for the 2-yr recurrence <br />interval. For the 10-yr recurrence interval, <br />Figure 2.2 gives an EI/R of 1.65, for an R10 of <br />116. <br />K: From Figure 2.2 (attached) using the result of the <br />soil sample in the Manzano and Louviers/Travessilla <br />soils, K 0.25. This is low for the area, uae 0.30 <br />LS:From Figure 2.3 (attached), with elope of 7.5% and <br />flow line of 400 feet: LS = 2. <br />VM: From Figure 2.8, with grass of 5% and less than 25% <br />weeds, VM = 0.35. <br />Then <br />and <br />A= 70x .30x2x .35 <br />= 14.7 tons/acre/year (2-yr rec. int.) <br />A 116 x .30 x 2 x .35 <br />= 24.4 tons/acre/yr (10-yr rec. int.) <br />Converting to acre-feet using a soil density of 95 <br />ibs/cu. ft: <br />14.7t/yr/acre x 2.1 acre x 20001bs x 1 cu ft =650 cu.ft. <br />ton ~-I~ <br />650 cu. ft./43560 sq ft/ac = 0.015 AF <br />24.4t/yr/acre x 2.1 acre x 20001bs x 1 cu ft =1080 cu.ft. <br />ton ~5~b <br />1080 cu. ft./ 43560 sq ft/ac = 0.025 AF <br />Assume that pond is cleaned every year and that the <br />10-year flow event occurs at the end of the year used for <br />the 10-year recurrence interval in the sediment analysis. <br />Thus use 0.025, rounded to 0.03 AFB as the sediment <br />volume. <br />
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