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<br />Page Two April 26, 1979 <br />pond will be included within the new <br />reclamation plan. <br />Sediment Pond Size Calculations <br />.91 acres equals 39,639 sq. ft. <br />1 ft. x 39,639 sq. ft. x .183 ft. (2.2 in.)= <br />7254 Cu. Ft. <br />7254 Cu. Ft. = 54,259 gal. <br />54,259 gal. - 50 = 1085 Cu. Ft. <br />Plus .2 acre ft. per acre = 7927 Cu. Ft. <br />Total volume = 9002 Cu. Ft. <br />It is proposed, therefore, that a 50 ft. x 50 ft. sediment <br />pond be excavated 3.60 feet deep in order to accommodate this type <br />of storm. <br />Sincerely, <br />Kenneth L. Schlagel <br />Geologist <br />KLS mf <br />