2020-06-19_REVISION - M1973021

• Permit No: M1973021
• IBM Index Class Name: REVISION
• Doc Date: 6/19/2020
• Doc Name: Request for Technical Revision
• From: Aggregate Industries
• To: DRMS
• Type & Sequence: TR7
• Email Name: ECS
• Email Name: MAC
• Email Name: AWA
• Media Type: D
• Archive: No

' Rock_Chute.xls Page 3 of 3
Rock Chute Design Calculations
' (Version WI-July-2010, Based on Design of Rock Chutes by Robinson, Rice, Kadavy, ASAE, 1998)
Project: Morrison Quarry- Basin B Outlet County: Jefferson
Designer: TPY Checked by:
' Date: 5/18/2020 Date:
V. Calculate the rock chute parameters (w/o a factor of safety applied)
' High Flow Low Flow
qt= 0.11 cros/m qt= 0.05 cros/m (Equivalent unit discharge)
D50(mm)= 110.26 > (4.34 in.) D50= 75.33 mm (Median angular rock size)
' n= 0.050 n = 0.047 (Manning's roughness coefficient)
z1 = 0.20 ft, z1 = 0.13 ft. (Normal depth in the chute)
A,= 0.1 ft2 A, = 0.0 ft2 (Area associated with normal depth)
Velocity= 7.36 fps Velocity= 5.60 fps (Velocity in chute slope)
Zmean= 0.10 ft. zmean= 0.06 ft. (Mean depth)
F, = 4.08 F, = 3.92 (Froude number)
' Lrock apron= 5.43 ft. ---- ---- (Length of rock outlet apron= 15*D50)
VI. Calculate the height of hydraulic iump height(coniugate depth)
' High Flow Low Flow
Z2= 0.57 ft. z2= 0.35 ft. (Hydraulic jump height)
Ohigh= 0.6 cfs Ohigh= 0.2 cfs (Capacity in channel)
' A2= 0.7 ft2 A2= 0.2 ft2 (Flow area in channel)
VII. Calculate the energy lost through the iump(absorbed by the rock)
High Flow Low Flow
E, = 1.04 ft. E1 = 0.61 ft. (Total energy before the jump)
E2= 0.59 ft. E2= 0.36 ft. (Total energy after the jump)
RE= 43.79 % RE= 41.65 % (Relative loss of energy)
Calculate Quantities for Rock Chute
-------Rock Riprap Volume------- -------Bedding Volume-------
Area Calculations Length(a)Rock CL Area Calculations
h= 0.69 Inlet= 9.84 h = 2.69 Bedding Thickness
' x, = 4.47 Outlet= 10.35 x, = 0.00 t1,t2 = 0.00 in.
L= 1.54 Slope= 79.78 L= 6.02
As= 3.09 2.5:1 Lip= 5.18 As= 0.00 Length ZV Bed CL
' x2= 4.00 Total = 105.15 ft. x2= 0.00 Total = 105.13 ft.
Ab= 9.89 Rock Volume Ab= 0.00 Bedding Volume
Ab+2*A5= 16.06 ft2 62.54 yd3 Ab+2*A5= 0.00 ft2 0.00 yd3
' -------Geotextile Quantity------- Note: 1)The radius is not considered when calculating
Width Length(a?Bot. Rock quantities of riprap, bedding,or geotextile.
2*Slope= 12.03 Total = 105.13 ft. 2)The geotextile quantity does not include over-
Bottom = 0.94 Geotextile Area overlapping(18-in. min.)or anchoring material
Total= 12.97 ft, 151.56 yd2 (18-in. min. along sides, 24-in. min.on ends).