2020-06-19_REVISION - M1973021

• Permit No: M1973021
• IBM Index Class Name: REVISION
• Doc Date: 6/19/2020
• Doc Name: Request for Technical Revision
• From: Aggregate Industries
• To: DRMS
• Type & Sequence: TR7
• Email Name: ECS
• Email Name: MAC
• Email Name: AWA
• Media Type: D
• Archive: No

' Rock_Chute.xls Page 2 of 3
Rock Chute Design Calculations
' (Version WI-July-2010, Based on Design of Rock Chutes by Robinson, Rice, Kadavy, ASAE, 1998)
Project: Morrison Quarry- Culvert A Outlet Chan County: Jefferson
Designer: TPY Checked by:
Date: 5/18/2020 Date:
I. Calculate the normal depth in the inlet channel
' High Flow Low Flow
y„= 1.60 ft. y„= 0.60 ft. (Normal depth)
Area= 5.1 ft2 Area = 0.7 ft2 (Flow area in channel)
Qhigh= 58.8 cfs QIOW = 42 cfs (Capacity in channel)
Scupstreamchannel= 0.065 ft/ft
' II. Calculate the critical depth in the chute
High Flow Low Flow
Yc= 2.22 ft. Yc= 0.77 ft. (Critical depth in chute)
' Area= 9.8 ft2 Area= 1.2 ft2 (Flow area in channel)
Qhigh= 58.8 cfs QicW= 42 cfs (Capacity in channel)
Hce= 2.77 ft. Hce= 0.97 ft. (Total minimum specific energy head)
' hcv = 0.55 ft. hcv= 0.20 ft. (Velocity head corresponding to yc)
10yc= 22.18 ft. (Required inlet apron length)
0.715yc= 1.59 ft. 0.715yc= 0.55 ft. (Depth of flow over the weir crest or brink)
III. Calculate the tailwater depth in the outlet channel
High Flow Low Flow
' Tw= 2.71 ft. Tw= 1.01 ft. (Tailwater depth)
Area= 14.7 ft2 Area= 2.0 ft2 (Flow area in channel)
Qhigh= 58.8 cfs QioW= 42 cfs (Capacity in channel)
' H2= 0.00 ft, H2= 0.00 ft. (Downstream head above weir crest,
H2=0, if H2<0.715'yc)
IV. Calculate the head for a trapezoidal shaped broadcrested weir
' Cd= 1.00 (Coefficient of discharge for broadcrested weirs)
High Flow
HP= 4.31 ft. 4.32 ft. (Weir head)
Area= 37.2 ft2 37.4 ft2 (Flow area in channel)
' Vo= 0.00 fps 1.57 fps (Approach velocity)
hpV= 0.00 ft. 0.04 ft. (Velocity head corresponding to Hp)
Qhigh= 58.8 cfs 58.8 cfs (Capacity in channel)
Trial and error procedure solving simultaneously for velocity and head
Low Flow
HP= 1.50 ft. 1.51 ft. (Weir head)
Area= 4.5 ft2 4.5 ft2 (Flow area in channel)
V. = 0.00 fps 0.93 fps (Approach velocity)
hp�= 0.00 ft. 0.01 ft. (Velocity head corresponding to Hp)
QioW= 4.2 cfs 4.2 cfs (Capacity in channel)
' Trial and error procedure solving simultaneously for velocity and head
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