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<br />;, <br /> <br />OjJ7Jl <br /> <br />RESERVOIR EV APORA nON <br /> <br />Date: 2-1-96 <br /> <br />e <br /> <br />Summary: <br /> <br />Phvsical Hydrolo~: <br />Net Reservoir Evaporation = [0.7 x (Hook Reading)] x Reservoir Area <br /> <br />Accountinll Hydrolo~: <br />Adjusted Net Reservoir Evaporation = [(0.7 x Hook Reading) + <br />(0.3 x Precipitation)] x Reservoir Area <br /> <br />Basic Equations: <br /> <br />Gross Evaporation = Net Evaporation + Precipitation <br /> <br />Net Pan Evaporation'" Hook Reading = Gross Pan Evaporation - Precipitation <br /> <br />Net Reservoir Evaporation = 0.7 x Pan Evaporation = 0.7 x Hook Reading <br /> <br />Phvsical H:ydrolou: <br /> <br />Ifall of the precipitation is kept in the reservoir and the evaporation pan is at the reservoir site, <br />the following equation applies: <br /> <br />e Net Reservoir Evaporation = [0.7 x (Hook Reading)] x Reservoir Area <br /> <br />If all of the precipitation is kept in the reservoir and the evaporation pan is Ill!1 at the reservoir <br />site, the following equation applies: <br /> <br />Net Reservoir Evaporation = [0.7 x (Hook Reading + Precipitation at the evaporation pan site) - <br />Precipitation at the Reservoir site] x Reservoir Area <br /> <br />The reservoir water volume balance equation for the Physical Hydrology is: <br /> <br />Change in storage = Inflow - Release - Net Reservoir Evaporation <br /> <br />Computed Inflow = Change in Storage + Release + Net Reservoir Evaporation <br /> <br />Example: <br /> <br />Change in Storage = 100 a.f <br />Reservoir Release = 200 a.f <br />Hook Reading = 2 inches <br />Precipitation = 1 inch <br />Reservoir Surface Area = 500 acres <br /> <br />e <br /> <br />Computed Inflow = 100 + 200 + [(0.7, x (2)) x 1/12 x 500] = 358.33 a.f <br />