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<br />Part (4) <br /> <br />The irrigator elects to pump 0.5 acre-ft/day for the first 32 <br /> <br />days of the season. What is the highest rate he can pump during the <br /> <br />., <br /> <br />remaining 118 days? <br /> <br />Try assumption that restriction on volume of stream depletion <br /> <br />will apply. <br /> <br />t T/a2 S = 32 days = 0.15, <br />-p- - - 209 days <br />(t + t.) T/aa S = 150 days = 0.72. <br />-~ -=. - - - 209 days <br /> <br />From Figure 3: <br /> <br />V, T/Qa2S = 0.057 <br />- - -- <br /> <br />~ = (0.057) (0.5 acre-ft/day) (209 days) <br /> <br />= 6.0 acre-ft <br /> <br /> ~ t, = (0.5 acre-ft/day) (32 days) = 16 acre-ft <br /> -- <br />25 acre-ft 6 acre-ft = 19 acre-ft = ~2 <br /> .!'l = 118 days <br /> raTti's 118 days 0.56. <br /> = = <br /> - - -- 209 days <br /> <br /> From Figure 1: ./O~8 <br /> :f2 /r;g,~ = 0.17 <br /> Qat" = 19 acre-ft/0.17 = 112 acre-ft <br />.' (112 + 16) acre-ft = 128 acre-ft, which is less than 150 acre- ft <br /> / <br /> <br />therefore the assumption that volume of stream depletion applies is <br /> <br />correc t. <br /> <br />~ = <br /> <br />112 acre-ft <br />118 days <br /> <br />= 0.95 acre-ft/day. <br /> <br />27 <br />