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<br />Part (3) <br /> <br />From Figure 2: if <br /> <br />t T/a"S = 0.15, <br />-p- - - <br /> <br />maximum q/Q = 0.13 <br />- - <br /> <br />when <br /> <br />therefore, maximum q = 0.13 (2 acre-ft/day) = 0.26 acre-ft/day <br /> <br />(t + t.) T / a" S = 0.25, <br />-p -1 - - - <br />- - <br /> <br />when <br /> <br />t + t = (0.25) (520 days) = 130 days, or 52 days <br />1> -~ <br /> <br />after pumping stops. <br /> <br />1082 <br /> <br />" <br /> <br />23 <br />