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<br />Part (1) <br /> <br />/Q = 0.14 acre-ft/day = 0 07 <br />1. _ 2 acre-ft/day . <br /> <br />~ <br />o <br />r;$) <br />~ <br /> <br />From Curve A (Fig. 1): <br />tT / a2 S = O. 15 <br />--- <br /> <br />t = (0.15) (sdf) = (0.15) (520 days) = 78 days <br />- <br /> <br />From Curve,B (Fig. 1): if <br />!:J./l~ = 0.15, <br />v/Qt = 0.02 <br />-- <br /> <br />v = (0.02) (2 acre-ft/day) (78 days) = 3.1 acre-ft. <br /> <br />During the 78-day pumping period, 3.1 acre-ft, out of a total <br /> <br />of 156 acre-ft pumped, is stream depletion. <br /> <br />21 <br />