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<br />. - <br /> <br />, " <br />G" : "t <br />JU ...... <br /> <br />RSS Concepts snd Methodology <br /> <br />, tluvJ <br />:\It" "" .b <br />1t'.L' "..1 S~T <br />0\ vn>' #~~ <br />fW,( <br />"D\v!- <br />e""",, <br /> <br />2. Reservoir Node 2 receives from ils input lime-series lable the current inflow <br />and ending storage. It accesses its functions to find hOw much to release. <br />These data exist, and hence it will be possible for Node 2 to solve its mass <br />balance equation for ending storage. Thus Node 2 is placed on the object <br />activation queue behind Node 1. <br />\,.~,?~ <br /> <br />.~"., <br />, <br /> <br />~.. I~I <br /> <br />Node 2 <br /> <br />t <br /> <br />Node 3 <br /> <br />;) dOl'> Y'l)\' ~ ovAf/~.u <br /> <br />~~ ?~().'" ,r <br />}/uv.J t{ <br />0' i)'\ <br /> <br />3. Reservoir Node 3 does not receive any data for ending storage or scheduled <br />releases. Since the releases Irom the upstream reservoirs at Node 1 and <br />Node 2 make up part 01 the total inflow to Node 3. and since these releases <br />from Node 1 and Node 2 have not yel been transferred to the inflow data <br />slots of Node 3, this reservoir node cannol solve its mass balance equation. <br />It therefore is not placed on the object activation queue. <br />Node 1 Node 2 <br />\1 <br />~ <br />Node 3 <br /> <br />t <br />Node 4 <br /> <br />4. Since the demands of Nodes 5 and 6. and the release Irom Node 3 are not <br />known yet. Node 4 cannot pertorm its operation, and hence is not placed on <br />the object activation queue. Since no inDUtlables supply time-series datalo <br />NQde 5 it does not Qat examned in this first iteration of the simulation proce. <br />dure. <br /> <br /><~ <br />~ dvl? M 3 b'-' <br />;~f{'w {r'ftt" ~ <br />0"<< flvu!5 /0 5 d <br /> <br />Node 3 <br /> <br />I <br />II <br />/Node4~ <br />Node 5 Node 6 <br /> <br />RSS Concepts and Methodology <br /> <br />15 <br />