Laserfiche WebLink
<br />30 <br /> <br />TECHNIQUES OF WATER-RESOURCES INVESTIGATIONS <br /> <br />s <br /> <br /> <br />y <br /> <br /> <br />x, <br /> <br />6 <br /> <br />4 <br /> <br />t: ~ <br />'" <br />~ <br />,... <br />-< <br />~ 0 <br /><r <br />::> <br />() <br />~ -2 <br /><r <br />~ <br />~ <br />~ -4 <br />" <br />u; <br />'" <br /><r <br /> <br />-6 <br /> <br />-s <br /> <br />-10 <br /> <br />o ~ <br /> <br />Figure ~1.-Multiple linear regression by the method of residuals. <br /> <br />4 <br />X, <br /> <br />4. Lines of equal S are logarithmically spaced <br />at twice the logarithmic scale of the paper <br />and are parallel. <br />To solve, separate the regression into two <br />parts by introducing an intermediate variable <br />Q.., (to an arbitrary scale) so that <br /> <br />and <br /> <br />Q..,=j(A, P) <br /> <br />Q..,~j(S, QlO)' <br /> <br />Consider the first relation, For a fixed P, the <br />model would be <br /> <br />Q..,=KA", <br /> <br />in which K is the intercept on the Q.., scale <br />(at A= 1) and n is the slope of the line. In this <br />example, n= 1.28, which is the ratio of the <br />linear vertical to horizontal lengths. When <br />P= 1.20, the intercept K is 78. To obtain this <br />intercept graphically requires a long curve <br />extension. It is simpler to compute the intercept <br />from some other value of A than one. For <br /> <br />6 <br /> <br />instance, for Q..,=I,OOO, A=7.3. Then <br /> <br />1,000=K(7.3)1.28, from which K=78. <br /> <br />Similarly, for Q..,= 10,000, A=44.5 and K =78. <br />Introducing P as a variable makes it neces- <br />sary to define the intercept K in terms of P <br />(because the intercept is different for each <br />value of P), The interval per tenth difference <br />in P when projected on the Q.., scale is 1.36, <br />that is, for each tenth increase in P, the inter- <br />cept increases 1.36 times (the intercept is on a <br />logarithmic scale). This increase can be meas- <br />ured for individual intervals or computed from <br />the total increase: For instance, for A= 10: <br /> <br />Q..,= 1,480 for P= 1.2, <br /> <br />and <br /> <br />Q..,=17,000 for P=2,O. <br /> <br />The increase for eight intervals is 17,000{ <br />1,480=11.5, and (1.356)'=11.5. <br />Then <br /> <br />K=78(1.36)IO(P-l.", <br /> <br />. <br /> <br />s <br /> <br />. <br /> <br />. <br />