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<br />7.3.1 Traffic Restoration Time <br /> <br />e <br /> <br />Traffic restoration time for each flood event is added to the overtopping time <br />for each event to obtain the total detour time. The traffic restoration time <br />can be estimated from: <br /> <br /> T = Ve(Pl - P ) 24 + A (P2 - P ) 24 + Mobilization Time <br /> r e - p p - <br /> Re Rp <br />Where: Tr = Traffi c restoration time, hr. <br /> Ve = Total embankment subject to overflow, CY. <br /> <br />Pl = Percent of embankment loss. <br />P = <br />e <br /> <br />Percent of embankment repair <br />where traffic interruption does not occur. <br /> <br />R = Rate of embankment repair, CY /day. <br /> e <br />A = Total pavement area subject to ove rfl ow, SY. <br /> P <br />P2 = Percent of pavement loss. <br />P = Percent of pavement repair where <br /> p traffic interruption does not occur. <br /> <br />e <br /> <br />R = Rate of pavement repair, SY/day. <br />p <br /> <br />Total detour time for each flood event is: T + overtopping time. <br />r <br /> <br />Example: For the Row Creek Crossing, the rates of repair are 3000 CY/day <br />for embankment and 2000 SY/day for pavement. The percent of time where <br />traffic delays do not occur are one percent for embankment and 5 percent for <br />pavement repairs. The mobilization time is negligible for the 100-year event <br />and 8 hours for the 200-year event. For the 50-year event, even though no <br />damage occurs, clean up of the roadway is required. This is assumed to be <br />possible without traffic interruption. Therefore, the detour time is the <br />overtopping time for the 50-year event. <br /> <br />Time of detour (T d) = t + overtoppi ng time(tot) <br /> r <br /> Td50 = o + 7 = 7 hours <br /> TdlOO = (214.8)(0.008) + (14.7)(0.012) + 0 + 20 <br /> = 23.6 hours <br /> <br />Td200 = (1718.4)(0.008) + (1391.9)(0.012) + 8 + 40 <br />= 78.5 hours <br /> <br />e <br /> <br />44 <br />