Laserfiche WebLink
<br />Thus, the wave celerity as determined with Eq. (35) is: <br /> <br />c = 0.682 (3.48) [5/3 - 2/3 (i~;2 )] = 3.25 milhr <br /> <br />The time of travel for the flood peak to the forecast point at mile 12.3 is <br />given by Eq. (36) as follows: <br /> <br />. <br /> <br />tp (X=12.3) = Tf + 12~3 = 0.75 + ~~2; <br /> <br />. <br /> <br />t - 4.54 hrs <br />p <br /> <br />To compute the peak stage at mile 12.3, the user must first compute the <br /> <br /> <br />K and m coefficients for that cross section. This is done by first reducing <br /> <br />the X-sectional data at mile 12.3 from table 1 as follows: <br /> <br />Table 6 -- TOPWIDTH VS. DEPTH DATA AT MILE 12.3 <br /> <br />Depth Topwidth <br />7 400 <br />17 770 <br />27 1330 <br />37 1400 <br /> <br />Substituting this reduced data into Eqs. (5)-(6a) produces a K value of <br /> <br /> <br />71.96 and an m value of 0.87. These values are substituted with the peak <br /> <br /> <br />flow into Eq. (8) to compute the peak depth at mile 12.3 as follows: <br /> <br />.. <br /> <br />= 1.49 ( 008)1/2 <br />a .045 . . <br /> <br />71.96 <br />(0.87 + 1)5/3 <br /> <br />= 23.12 <br /> <br />b = 0.87 + 5/3 = 2.53 <br /> <br />1-30 <br />