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<br />h <br />x <br />c <br /> <br />= (~) l/b <br /> <br />= 1.49 S1/2( K }= 27.29 <br />a n (;;;, + 1 )5/3 <br /> <br />b = m + 5/3 = 2.49 <br /> <br />= (57480) 1/2.49 <br />hx 27.29 <br />c <br /> <br />hx = 21.61 <br />c <br /> <br />This value of h is substituted into Eq. (28) to re-evaluate the <br />x <br />original estimate for 6 : <br /> <br />6 = <br /> <br />h + h <br />max x <br />2 h <br />max <br /> <br />= <br /> <br />26.49 + 21.61 <br />2 (26.49) <br /> <br />= 0.91 <br /> <br />Because the re-evaluated 6 is within (:5%) of the original estimate <br /> <br /> <br />for 6, the initial calculations are acceptable and the attenuation of the <br /> <br /> <br />flood peak may be predicted using the curves for Fc = 0.25 and interpolating <br /> <br />* <br />V = 1.15. <br /> <br />* <br />The dimensionless distances (Xi ) to at mile 12.3 is as follows: <br /> <br />* <br />Xl <br /> <br />_ 12.3 _ <br />- X - <br />c <br /> <br />12.3 3 <br />(20600) = .15 <br />5280 <br /> <br />1-28 <br />