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Last modified
1/25/2010 6:48:26 PM
Creation date
10/5/2006 1:17:53 AM
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Template:
Floodplain Documents
County
Statewide
Community
State of Colorado
Stream Name
All
Basin
Statewide
Title
Manual For Estimating Flood Characterstics of Natural Flow Streams in Colorado
Date
1/1/1976
Prepared For
State of Colorado
Prepared By
CWCB
Floodplain - Doc Type
Educational/Technical/Reference Information
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<br />._1_. _I <br /> <br />MANUAL FOR ESTIMATING FLOOD CHARACTERISTICS <br /> <br />33 <br /> <br />Multiply Plains Region discharges by the reduction factor (R) to obtain <br />the discharges to be used for the Plains Region. <br /> <br />QIO -0.64{1,530 ft3/s)- 980 ft3/s <br />Qso -0.64{3,420 ft3/s)-2,190 ft3/s <br />Qloo-0.64{4,640 ft3/s)-2,970 ft3/s <br />Qsoo-0.64{9,290 ft3/s)-5.950 ft3/s <br /> <br />Compute QIO, QSO, QIOO' and Qsoo for the Mountain Region for area above <br />7,500 f t. <br /> <br />QIO =0.12Ao.8ISpI.S92_0.12{6.3)0.815{19)I.S92_0.l2{4.48) (lO8.59)= 58 ft3/s <br /> <br />QSO =0.91AO.79Spl.110=0.91{6.3)0.795{19)1.110=0.91{4.32){ 26.27)=103 ft3/s <br /> <br />QIOO=l. 88Ao. 787pO. 932=1 .88{6. 3) 0.787 (19) O. 932=1 .88{4. 26) ( 15.55)=125 ft3/s <br /> <br />Qsoo=8.70AO.766pO.S60=8.70{6.3)O.765{19)0.S60=8.70(4. 10) ( 5.20)=186 ft3/s <br /> <br />Select the highest discharge for each recurrence interval. In this case <br />the reduced discharges for the Plains Region are used. <br /> <br />Compute the flood depths from depth equations for both regions and use <br />the greatest depth for each recurrence interval. <br /> <br />Flood depths--Plains Region <br /> <br />010 =35.5Ss-0.462_35.5(111)-0.462=35.5(0.11)=3.9 ft <br />050 =52.1SS-0.S00=52.1(111)-0.SOO=52.1{0.09)=4.7 ft <br />0100=59.3Ss-0.SI7=59.3(111)-0.SI7=59.3(0.09)=5.3 ft <br />Osoo=77.3SS-0.SS3=77.3(111)-0.SS3=77.3(0.07)-5.4 ft <br /> <br />~ <br /> <br />Flood depths--Mowdain Region <br /> <br />.j <br /> <br />010 =0.44Ao.l96pO.347=0.44{6.3) o.I'I6(l~J) 0.347=0.4Ij (1.43) (2.78)-1.8 ft <br />Oso =1.05AO.192pO.133=1.05{6.3)0.192(19)0.133_1.0S(1.42) (1.48)=2.2 ft <br />0100=1.44AO.187pO.OS9=1.44(6.3)0.187{1~l)0.OS9_1.41.(1.41) {1.19)=2.4 ft <br />0500=1. 94AO.184_1. 94 (6. 3) o. HJ4_1. 94( 1.40)=2. 7 ft <br /> <br />Use the flood depths computed from the Plains Region relation.. <br />
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