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<br />Solution. Fitting a curve of the form of Eq 5 through the bound2ry <br />of the valley one finds M : 0.278 ang C = 175 ftO.722 (dimensions of C <br />are ft to the (l:M) power). TakinCl Y = 86 ft, one finds by Eq~ 7 C = 7 <br />and by Eqs. 3 : Lo = 86,000 ft or 16.3 mi., Vo = 10.54 ftlsec, To = 2.265 <br />hr and 10 = 0.20. <br /> <br />Using the graphs in Figs. A2, A3 values of tw at the desired locations <br />are obtained for fo= 0.10 and Fo = 0.50, respectively, and r = 0, C = 7. <br />In a similar way, from Fiqs. A8, A9 values of tw are found for Fo = 0.10 <br />and 10 = 0.50, respectively, and M = 0.50, C = 7. Linear interpolation <br />yields the values of tw for Fo : 0.20 and each value of M. Finally, a <br />second interpolation between the latter yields values of tw for 10 = 0.20 <br />and M : 0.278. An arrangement of data in table form, as shown in Table 1, <br />makes the task easier" <br /> <br />A completely analogous procedure using the appropriate graphS in <br />Appendices Band C yields the values of YM and tM as shown in Tables 2 <br />and 3. <br /> <br />. <br /> <br />. <br /> <br />. <br /> <br />E <br />