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<br />WORKSHEET W-l <br /> <br />DAM FAILURE PEAK DISCHARGE <br /> <br />DAM NAME: <br /> <br />Locr LAkE <br />{!%RADO <br /> <br />CALCULATIONS BY: .::T." VAAl SCIVeR <br />DATE: q-I-8e <br /> <br />LOCATION: <br /> <br />PHYSICAL DATA: <br /> <br />zLl <br />Crest Width. CW = 8 <br /> <br />Ft. Spillway Freeboard. FB =.3 Ft. <br />Ft. Normal Capacity. V = 6$0 Acre Feet <br /> <br />Height. H = <br /> <br />Embankment Slopes: Upstream (Zl) = <br /> <br />2 :1 Downstream (Z2) = 1.5 :1 <br /> <br />Crest Length. LC = ~~~ <br /> <br />Ft. Surface Area. A = <br /> <br />75 <br /> <br />Ac. <br /> <br />Kl = (.2H+IO)/cw = /. 85 <br />min. 0.5!K1~1.5 max. <br /> <br />use Kl = /.5 <br /> <br />K2=(H6.01)(LC-.543)(A4.45)(V-5.39) = a.904 <br />For V/H< 200 . min. 0.5~K25.1.5 max. <br />For 200~v/H~1000. min. 0.05~K~1.5 max. <br />For V/H>lOOO . min. 0.005<K2<1.5 max. <br />use K2 = O.q~t,t -- <br /> <br />K3 =(-2-).5 = ;.20 <br />Zl+Z2 <br /> <br />K4 = erosiveness of embankment materials <br /> <br />min. 0.5!K3!1.5 max. <br />use K3 = ;.ZO <br /> <br />0.5 ! K4 ~ 1.0 5 K4 ~ 1.5 <br />tight stable erosive <br /> <br />use K4 = /.25 <br /> <br />ESTIMATED DAM FAILURE PEAK DISCHARGE. Qp CFS: <br /> <br />K =(~)(Kl)(K2)(K3)(K4) = <br />H <br /> <br />I.Se? <br /> <br />-0.10 <br />Tp = (3.3?)(v.093)(e-1.?KV ) = 1.15 Hrs. (Kin. 0.25!Tp) <br /> <br />Qp = 24.2 v = <br />Tp <br /> <br />/3728 <br /> <br />cfs <br /> <br />8 <br /> <br />I <br />