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<br />equation: <br /> <br />Equation (13) is solved by trial and error until: <br /> <br />h = he - dc <br />v <br /> <br />For an ogee spillway, the discharge coefficient, C q' is computed as: <br /> <br />C Q = C c * ( ~ )E <br />hd <br /> <br />where: <br /> <br />C c = coefficient based on ratio of he to he, Table 1 <br />d. = depth of approach channel in feet <br />E = exponent based on ratio of he to hd, Table 1 <br /> <br />With no tailwater submergence, the spillway discharge is then: <br /> <br />Q=C *L *h <br />Q E e1.5 <br /> <br />Tailwater elevation may be computed from specific energy as: <br /> <br />het = 0.9 * (h . + E ./E . ) <br /> <br />where: <br /> <br />het = specific energy at toe of spillway <br />he = specific energy at crest of spillway <br />E. = elevation of spillway crest <br />E. = elevation of spillway apron <br /> <br />(14) <br /> <br />(15) <br /> <br />(16) <br /> <br />(17) <br /> <br />Tailwater depth is then computed by trail and error from the following <br /> <br />(het - D) * D 2 = 1 * (Q/L.) <br />2g <br /> <br />where: <br /> <br />D = tailwater depth <br />Q = discharge <br />L . = width of spillway apron <br /> <br />A submergence coefficient is interpolated from Table 2 using: <br /> <br />hd + D <br />he <br /> <br />= he + E - E <br />. . <br />he <br /> <br />and <br /> <br />7-S0 <br /> <br />(18) <br /> <br />(19) <br />